Exercise 2.14 A corridor has the form indicated in Figure 2.11. The maxi- mum length L of a rod that can pass from one e

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Exercise 2.14 A corridor has the form indicated in Figure 2.11. The maxi- mum length L of a rod that can pass from one e

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Exercise 2 14 A Corridor Has The Form Indicated In Figure 2 11 The Maxi Mum Length L Of A Rod That Can Pass From One E 1
Exercise 2 14 A Corridor Has The Form Indicated In Figure 2 11 The Maxi Mum Length L Of A Rod That Can Pass From One E 1 (58.94 KiB) Viewed 146 times
Also apply the Secant method to solve this problem. Be clear
aboutthe initial values you use to start each method.
Exercise 2.14 A corridor has the form indicated in Figure 2.11. The maxi- mum length L of a rod that can pass from one extreme to the other by sliding on the ground is given by L = 12/(sin(T-9-a)) +11/ sin(a), where a is the solution of the nonlinear equation cos(TT-1-a) 1 cos(a) 0. (2.38) sinº (TT--a) sinº(a) Compute a by Newton's method when l2 = 10, l1 = 8 and y = 37/5.
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