E H Sample 1 Sample 2 Sample 3 Sample 4 12.0913 11.8590 11.9687 12.0387 0,2061 0.2072 0.2204 0.2204 12 12 12 12 0.0376 0

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E H Sample 1 Sample 2 Sample 3 Sample 4 12 0913 11 8590 11 9687 12 0387 0 2061 0 2072 0 2204 0 2204 12 12 12 12 0 0376 0 1 (73.32 KiB) Viewed 27 times

E H Sample 1 Sample 2 Sample 3 Sample 4 12 0913 11 8590 11 9687 12 0387 0 2061 0 2072 0 2204 0 2204 12 12 12 12 0 0376 0 2 (28.9 KiB) Viewed 27 times

E H Sample 1 Sample 2 Sample 3 Sample 4 12 0913 11 8590 11 9687 12 0387 0 2061 0 2072 0 2204 0 2204 12 12 12 12 0 0376 0 3 (28.71 KiB) Viewed 27 times

E H Sample 1 Sample 2 Sample 3 Sample 4 12 0913 11 8590 11 9687 12 0387 0 2061 0 2072 0 2204 0 2204 12 12 12 12 0 0376 0 4 (24.87 KiB) Viewed 27 times

E H Sample 1 Sample 2 Sample 3 Sample 4 12.0913 11.8590 11.9687 12.0387 0,2061 0.2072 0.2204 0.2204 12 12 12 12 0.0376 0.0378 0.0402 0.0402 0.025882863! E Sample 1 Sample 2 Sample 3 Sample 4 12.03 11.88 11.56 11.63 Average 12.03 11.33 11.63 11.7 STD 12.06 11.72 11.53 11.6 Mean 12.19 11.92 11.76 11.83 STE 12.12 12.11 11.91 11.98 12.08 11.69 11.65 11.72 12.06 11.58 11.81 11.88 11.65 11.82 12.04 12.11 12.4 12.13 11.95 12.02 11.66 11.88 11.93 12 12.12 12.09 12.14 12.21 11.91 11.58 12.1 12.17 12.23 12.18 11.94 12.01 11.89 11.53 12.22 12.29 12.04 11.92 12.33 12.4 12.36 11.98 11.94 12.01 12.1 12.03 11.86 11.93 11.78 11.73 11.77 11.84 12.21 11.79 12.17 12.24 11.8 12.09 11.78 11.85 12.31 11.57 12.01 12.08 12.28 11.92 12.05 12.12 12.3 11.93 11.99 12.06 12.48 12.19 12.31 12.38 12.04 11.72 12.19 12.26 12.18 11.93 11.98 12.05 11.95 11.92 12.18 12.25 11.98 11.86 11.86 11.93 12.24 11.85 12.31 12.38 12.26 11.9 12.16 12.23

Conduct a hypothesis test for each sample the 0.01 evel of ice. Use the same standard deviations in calculating the test statistie (ou may need to use the appropriate acondo table or technology to answer this question. Round your best statistics to two decimal pace ed your values to four decimal places Samole Find the test statistic and value Dvo State your condusion Raject There is sufficient sidence to concude that the mean is significantly different from 12. Oct There is insufficient evidence to conclude that the mean is cantiterer trom 12. Do not reject There insufficient evidence to conduct at the mean scanty offerent from 12 Do not reject No. There is sufficient evidence to conduce at the means picant ferent from 12 Sample Find the best statistic and p-value Dvalues State your conclusion Reject There is sufficient evidence to conclude that the mean is significantly rent from 12 Reject There is insuficient evidence to condude that the mean is significantly afferent from 12 Do not reject There is insufficient evidence to conclude that the mean is significany offerent from 12. Do not reject He: There is some evidence to conclude that the mean is significant different from 12 Sample 3 Find the best statistic and p-value test statistic - pre- State your conclusion Reject H. There is sufficient evidence to conclude that the mean is significantly different from 12. Reject Hy. There is insufficient eedence to conclude that the mean is significantly different from 12.

Dject Ma. There in evidence to conclude that the means incantly different from 12 Do not get Ho. There is suficient evidence to conclude that the mean is significant different from 12 Samole Find the best statistic and testas D-value State your conclusion Raject There wicient evidence to conclude that the means in afferent from 12 Reject H. There is insufficient evidence to conclude that the mean is sgncantly different from 12 Do not reject. There is sufficient evidence te conclude that the means significantly afferent from 12. Do not reject Ho, There assumont evidence to conclude that the mean is significantly different from 12 Based on the hypotheses tests, which samole's need corrective action select all that apply Sami Sample 2 Sample Sample No samples and corrective action Control Limit Computea 99% confidence interval for the population mean - 12 such that, as long as a sample means within those limits, the process will be condered to be operating sanctory X exceeds the upper limit or if x below the lower corrective action will be taken. These mits are referred to as upper and lower controls for quity control purposes to Compute the sample mean for each of the four samples sami Sample2 sample 3 Sample 4 *- that only!

Computea 99% confidence interval for the population 12 tuch that as long as a new sample mean is within these limits, the process will be considered to be operating satisfactory exceeds the upper ritor it below the lower limt, corrective action will be taken these ints are referred to as upper and lower controllimits for culty control proves to Compute the sample mean for each of the four sampit sample sample 2 pample 3 sample 4 Based on the sample means and control tints, which samole!) need corrective action? [Select all the apply) Sample 1 Sample 2 Sample Sample 4 No samples need corrective action Level of significance Discuss the implications of changing the level of significance to larger value. What mistake or error could increase the level of significance increased? Increasing the level of significance will cause the null hypothesis to be rejected doften. Although this may mean guider corrective action when the process is rect control, also means there will be higher error probability of Select the process when the processed operating satisfactory. This would be an increase in the probability of making a type ETTE