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0.3 m o 0.9 m VB0 А B A 3-kg rod OA is initially hanging vertically when a 0.6 kg block B, sliding on a horizontal surface with negligible friction with a velocity of Veo= 3.2m/s, strikes the rod at its end A. 1. If the blocks velocity after the impact is VB1 = 0.16 m/s what is the coefficient of restitution between block B and bar OA?
2. Which of the following is the most ideally constructed momentum-impulse diagram for the system of block B and bar OA together? ROAL O 0 0 labour G + G. B A MV А А A B B 0 0 O. G. + G. G 4 А A > ROAD 0 0 0 G. + G. G D C. ON החיתות A B B Rat 0. 0 G. G. А 1 B 3. Which of the following moment of momentum equations about O is CORRECT and can be used to solve for the angular velocity of rod OA? A Movgo (0.9) = mBVB1(0.9) + TQAwOA1+ mo (0.600A)(0.3) B mg V30(0.9) = mBVB1(0.9) + moa(0.3w011) (0.3) С mg 180 (0.9) = mBV81(0.9) +loAWOA1+ moa(0.3wOA1) D. MgVso(0.9) = mBVB1(0.9) + 10AW0A +moa 0.3W0A) (0.3) 4. What is the impulse exerted by rod OA on block B?