Q2: A bar is supported between the walls at X and Y. The bar has a cross sectional area of 4700 mm? A load Fz = 12 kN is applied at point Z. Calculate the reactions forces at the walls at X and Y. Assume the Modulus of Elasticity is 190 GPa. X Fz = 12 kN Z 2 m Y
Formula and Materials sheet: Factor of Safety = U.T.S./6 O =P/AG = E€ o = Mc/ 8=PL/(AE) 8= a *L* AT T = Tc/) T = P/A T = GY = TL/(JG) 8 = PL/(AE) Pr = $y* c/ J = 3.14*c*/2 (Solid Bar) J = 3.14*(c29-C1")/2 (Hollow Bar) I = bh/12 (Rectangle) 1-3.14*r*/4 (Circle) 1x = le+Ad? ΥΣΑ = ΣyA Power Force *Velocity=Work/time Key: o=Stress, t=Shear Stress, P=Force, A=Area, M=Moment, I=Moment of Inertia, E=Young's Modulus, E=strain T=Torque, Ty=Elastic Torque, J=Polar Moment of Inertia, G=Modulus of Rigidity, Y-Shear Strain, =Angle of Twist, L=Length, 8=deformation, b=breadth, h-height, d, y, Y, C=distance or radius, pr-radius of elastic core, a=coefficient of expansion, U.T.S.= Ultimate Tensile Strength Material Youngs Modulus (GPa) 200 Yield Stress (MPa) Ultimate Tensile Strength (MPa) Modulus Coefficient of Rigidity of Expansion (GPa) (10*/C) 200 12 Steel Aluminium 70 30 23 250 (Normal) 150 (Shear) 95 (Normal) 55 (Shear) 220 (Normal) 150 (Shear) 12 400 (Normal and Shear) 110 (Normal) 70 (Shear) 70 (Normal and Shear) Copper 120 40 17 Concrete 25
Q2: A bar is supported between the walls at X and Y. The bar has a cross sectional area of 4700 mm? A load Fz = 12 kN is
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Q2: A bar is supported between the walls at X and Y. The bar has a cross sectional area of 4700 mm? A load Fz = 12 kN is
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