For the BIT network below: Vo = 14V.R, - 68222, R = 1049, 0, -120, R = 56 R: -0.82, 4, R = 3,369.C = 0,471F.C=-5pF.C.-8p

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answerhappygod
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For the BIT network below: Vo = 14V.R, - 68222, R = 1049, 0, -120, R = 56 R: -0.82, 4, R = 3,369.C = 0,471F.C=-5pF.C.-8p

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For The Bit Network Below Vo 14v R 68222 R 1049 0 120 R 56 R 0 82 4 R 3 369 C 0 471f C 5pf C 8p 1
For The Bit Network Below Vo 14v R 68222 R 1049 0 120 R 56 R 0 82 4 R 3 369 C 0 471f C 5pf C 8p 1 (33.06 KiB) Viewed 17 times
For the BIT network below: Vo = 14V.R, - 68222, R = 1049, 0, -120, R = 56 R: -0.82, 4, R = 3,369.C = 0,471F.C=-5pF.C.-8pF.C- 12pF.C. -40 pF.C.,BpF 0.474F.C. - 204F, B = 120. (total 12 points) Determine ... and f ( points) b. Determine , and fw, 15 points) What is the lower cutoff frequency and higher cutoff frequency of the amplifier?(2 points) a. c. Vec 14V 5.GE 6上 If 0.47UF 0.47UF -MH + 0.82 R233.3k R₂ lokn w RE CAT ouf 1. Solution:
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