Note that f(x0,1.) = 0 at the equilibrium point due to a zero acceleration. Substituing Eq. (4) and Eq. (5) into Eq.(3)
Posted: Mon May 09, 2022 8:02 am
Note that f(x0,1.) = 0 at the equilibrium point due to a zero acceleration. Substituing Eq. (4) and Eq. (5) into Eq.(3) yields: er E = dat dt2 ît ailx=xo,i=i. əxlx=xo,i=i. revizia (6) fjeroizio calculate a and b at the af Let a= and b = əxlx=xo,i=io equilibrium point Xo = 6.94mm, io = 0.3A. D = 2 Derive the transfer function of the linearized system Eq. (6) at the (S) equilibrium point: P(s) 1(s) =