Note that f(x0,1.) = 0 at the equilibrium point due to a zero acceleration. Substituing Eq. (4) and Eq. (5) into Eq.(3)

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Note That F X0 1 0 At The Equilibrium Point Due To A Zero Acceleration Substituing Eq 4 And Eq 5 Into Eq 3 1 (51.64 KiB) Viewed 23 times

Note that f(x0,1.) = 0 at the equilibrium point due to a zero acceleration. Substituing Eq. (4) and Eq. (5) into Eq.(3) yields: er E = dat dt2 ît ailx=xo,i=i. əxlx=xo,i=i. revizia (6) fjeroizio calculate a and b at the af Let a= and b = əxlx=xo,i=io equilibrium point Xo = 6.94mm, io = 0.3A. D = 2 Derive the transfer function of the linearized system Eq. (6) at the (S) equilibrium point: P(s) 1(s) =