function SortSmallestToLargest (entries): sorted_entries = {} while entries is not empty: smallest_entry = entries[0] fo

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answerhappygod
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function SortSmallestToLargest (entries): sorted_entries = {} while entries is not empty: smallest_entry = entries[0] fo

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Function Sortsmallesttolargest Entries Sorted Entries While Entries Is Not Empty Smallest Entry Entries 0 Fo 1
Function Sortsmallesttolargest Entries Sorted Entries While Entries Is Not Empty Smallest Entry Entries 0 Fo 1 (36.86 KiB) Viewed 25 times
EXPLAIN THE LOGIC BEHIND PROPERLY. NOT JUST THE ANSWER OR
DOWNVOTE !!!!!!!!!!!!
function SortSmallestToLargest (entries): sorted_entries = {} while entries is not empty: smallest_entry = entries[0] foreach entry in entries: if (entry <smallest_entry): smallest_entry = entry sorted_entries.add(smallest_entry) // 0(1) entries.remove(smallest_entry) // 0(1) return sorted_entries Which of the below answers describes the time complexity of the above code most accurately? Pick ONE option O(n) O(n) O(nlogn) O(logn)
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