hi can someone please kindly explain how do i solve this
question... i am really confused with this topic and need some
clarification:
below are my doubts...
1) what is 2 and CB in 0x21CB means? as i know 1 mean r1
right?
2) please explain the increment how to derive r1 and r 15
and
3) please explain like how to derive r15 from the value of
r3?
Registers r1, r3 and r15 hold the values OxCCDDEEFF, OxFEDCBA98 and Ox00000108 respectively. What values are held by registers r1, r3 and r15 after the execution of the move (immediate) instruction with machine code 0x21CB? 15 11 10 8 7 0 Opcode Rd Immediate value r1:=0x000000AB, r3:=0xFEDCBA98, r15:=0x0000010C O r1:=0x000000AO, r3:=0xFEDCBA9C, r15:=0x0000010B r1:=0x000000AO, r3:=0xFEDCBA9C, r15:=0x0000010A r1:=0x000000CB, r3:=0xFEDCBA98, r15:=0x0000010A
Registers r1, r3 and r15 hold the values OxCCDDEEFF, OxFEDCBA98 and Ox00000108 respectively. What values are held by reg
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answerhappygod
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Registers r1, r3 and r15 hold the values OxCCDDEEFF, OxFEDCBA98 and Ox00000108 respectively. What values are held by reg
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