For the beam shown below, draw the reactions in the positive coordinate directions and calculate: w lb/ft Plb 0 A B Ах L

[answerhappygod]

1 (45.34 KiB) Viewed 32 times

2 (24.6 KiB) Viewed 32 times

3 (10.61 KiB) Viewed 32 times

For the beam shown below, draw the reactions in the positive coordinate directions and calculate: w lb/ft Plb 0 A B Ах L ft a ft b ft BY COLLAPSE IMAGES W = 50 lb/ft P = 60 lb L=7 ft a = 6 ft b = 2 ft @ = 55 deg
The horizontal reaction at A. lb ENTER 3 tries remaining. 1 point(s) possible The vertical reaction at A. lb ENTER 3 tries remaining. 1 point(s) possible The vertical reaction at B. lb ENTER 3 tries remaining. 1 point(s) possible The range for section 1. ( ) ft ENTER 3 tries remaining, 1 point(s) possible The shear force equation for section 1. lb ENTER 3 tries remaining. 1 point(s) possible
The bending moment equation for section 1. Ib.ft ENTER 3 tries remaining, 1 point(s) possible The range for section 2. ( <x< ) ft ENTER 3 tries remaining. 1 point(s) possible The shear force equation for section 2. 1b ENTER 3 tries remaining. 1 point(s) possible The bending moment equation for section 2. Ib.ft ENTER 3 tries remaining. 1 point(s) possible The range for section 3. ( <x< ) ft ENTER 3 tries remaining. 1 point(s) possible
The shear force equation for section 3. lb ENTER 3 tries remaining. 1 point(s) possible The bending moment equation for section 3. Ib.ft ENTER 3 tries remaining. 1 point(s) possible