++ K 1 = 2.5 m e = 5 cm f = 5 cm g= 10 cm E=210 GPa a= 1.2 10 5 1/°C F. 8 + 12 + 1/2 + + B a) What is the name, symbol a

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answerhappygod
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++ K 1 = 2.5 m e = 5 cm f = 5 cm g= 10 cm E=210 GPa a= 1.2 10 5 1/°C F. 8 + 12 + 1/2 + + B a) What is the name, symbol a

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K 1 2 5 M E 5 Cm F 5 Cm G 10 Cm E 210 Gpa A 1 2 10 5 1 C F 8 12 1 2 B A What Is The Name Symbol A 1
K 1 2 5 M E 5 Cm F 5 Cm G 10 Cm E 210 Gpa A 1 2 10 5 1 C F 8 12 1 2 B A What Is The Name Symbol A 1 (108.84 KiB) Viewed 24 times
++ K 1 = 2.5 m e = 5 cm f = 5 cm g= 10 cm E=210 GPa a= 1.2 10 5 1/°C F. 8 + 12 + 1/2 + + B a) What is the name, symbol and unit of the tipical strain of the beam element under bending? b) Find the maximum allowable value of the F concentrated force, if the allowable stress is = +120 MPa ! c) Determine the curvature (specific rotation) of the cantilever at cross-section K! d) Determine the normal strain araising at point B of cross-section K under the concentrated for given in question b). (Give the symbol of the strain with indices, correct sign and unit.) e) What would the curvature of the cantilever at cross-section K be if the concentrated force was replaced by a nonuniform thermal change 4To = +25 °C (bottom), 4T,= -25 °C (top)?
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