By Using Comsol Program Solve These Questions I Attach Photos With Coefficient Parameter And Processes 1 (112.92 KiB) Viewed 17 times
I attach photos with coefficient, parameter and
processes:
By Using Comsol Program Solve These Questions I Attach Photos With Coefficient Parameter And Processes 2 (18.42 KiB) Viewed 17 times
1. Which is the optimal volume for your flowrate to obtain the lowest COD in the effluent (consider that all the biomass will be eliminated in the secondary clarifier). Effluent COD can be calculated as: COD (MgCOD.[!) = Xs + Xp +X, + S + Ss 2. With the optimal volume do the following graphs and shortly comment them (graphs should have an appropriate title, legend, axis names and units): a) One graph representing heterotrophic and autotrophic biomass b) Another representing X5, Xp, X1, S, S, and the total COD in the outlet c) Finally, a graph representing nitrogen forms Syd, Sno, Snh, Xnd and the total N in the outlet Ideas on what you can comment from these graphs: What happen with the autotrophic microorganisms? Why? Which are the components (from total COD/N) with a higher concentration? Why? Is the ammonia (SNH) eliminated? Why? If not, how can we modify the design to remove also this ammonia? 3. Do this plant (with the optimal volume) meet the discharge requirements (assume that this plant treats the water for <10000 p.e., only COD limits). Will this plant meet the requirements if the inlet flowrate increases a 10%? What will be the new effluent COD?
11 11 11 11 11 11 11 11 I! v10_1 -iX_B v10_2 -iX_B v10_3 -iX_B-(1/Y_A) v10_6 1 v11_6 - 1 v11_8 1 v12_4 ix_B-fp*ix_P v12_5 iX_B-fp*ix_P v12_8 - 1 v13_1 -iX_B/14 v13_2 ((1-Y_H)/(14*2.86*Y_H))-ix_B/14 v13_3 -(ix_B/14)-(1/(7*Y_A)) v13_6 1/14 V2_1 -1/Y_H V2_2 -1/Y_H V2_7 1 V4_4 1-fp V4_5 1-fp V4_7 -1 V5_1 1 V5_2 1 V5_4 - 1 V6_3 1 V6_5 - 1 v7_4 fp v7_5 fp V8_1 -((1-Y_H)/Y_H) "" V8_3 -((4.57-Y_A)/Y_A) v9_2 -((1-Y_H)/(2.86*Y_H)) V9_3 1/Y_A 11 1 11 11 11 11
11 11 Þ_A "0.132 [1/d]" b_H "0.62 [1/d]" fp 0.08 iX_B 0.086 ix_P 0.06 K_NH "1 [mol/m^3]" KX 0.03 ka "0.08 [m^3/(mol*d)]" kh "3 [1/d]" KNO "0.5 [mol/m^3]" KO_A "0.4 [mol/m^3]" "" KO_H "0.2 [mol/m^3]" Ks "20 [mol/m^3]" mu_A "0.8 [1/d]" mu_H "6 [1/d]" NB 0.8 NH 8.4 YA 0.24 Y_H 0.67 11 11 1111 11 11
p1 mu_H* (re.c_ss/(Ks+re.c_ss))*(re.c_so/(KO_H+re.c_so))*re.c_XB_H p2 mu_H* (re.c_ss/(Ks+re.c_ss))*(KO_H/(KO_H+re.c_s0))*(re.c_SNO/(KNO+re.c_SNO)) *NB*re.c_XB_H p3 mu_A* (re.C_SNH/(K_NH+re.C_SNH))*(re.c_so/(KO_A+re.c_so))*re.c_XB_A p4 b_*re.c_XB_H p5 b_A*re.c_XB_A po ka*re.c_SND*re.c_XB_H p7 kh* ((re.c_Xs/re.C_XB_H)/(K_X+(re.c_Xs/re.C_XB_H)))*((re.c_so/(KO_H+re.c_50)) +NH* (KO_H/(KO_H+re.c_50))*(re.C_SNO/(KNO+re.C_SNO)))*re.C_XB_H "" p8 p7* (re.c_XND/re.c_Xs)
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