2. [3/4.54 Points] DETAILS PREVIOUS ANSWERS SERPSE10 10.1.OP.002. MY NOTES PRACTICE ANOTHER During a certain time interv

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2 3 4 54 Points Details Previous Answers Serpse10 10 1 Op 002 My Notes Practice Another During A Certain Time Interv 1 (408.56 KiB) Viewed 24 times

2. [3/4.54 Points] DETAILS PREVIOUS ANSWERS SERPSE10 10.1.OP.002. MY NOTES PRACTICE ANOTHER During a certain time interval, the angular position of a swinging door is described by 0 = 5.02 + 9.6t+ 2.08t2, where is in radians and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the door at the following times. (a) t = 0 0 = 5.02 rad @= 9.6 rad/s rad/s² a = 4.16 (b) t = 2.97 s Ꮎ = 51.87 rad = 15.78 X @ Have you obtained a general equation for the angular speed as a function of time? Once you have that result you can put in the specific value for t. rad/s = 35.81 X α The equation for is quadratic in t. What does this tell you about the acceleration? rad/s² Need Help? Read It Watch It