- A 1 8 Kg Object Oscillates At The End Of A Vertically Hanging Light Spring Once Every 0 60 S V Part A Write Down The Eq 1 (20.06 KiB) Viewed 22 times
- A 1 8 Kg Object Oscillates At The End Of A Vertically Hanging Light Spring Once Every 0 60 S V Part A Write Down The Eq 2 (29.91 KiB) Viewed 22 times
- A 1 8 Kg Object Oscillates At The End Of A Vertically Hanging Light Spring Once Every 0 60 S V Part A Write Down The Eq 3 (37.7 KiB) Viewed 22 times
- A 1 8 Kg Object Oscillates At The End Of A Vertically Hanging Light Spring Once Every 0 60 S V Part A Write Down The Eq 4 (51.44 KiB) Viewed 22 times
V Part A Write down the equation giving its position y(+ upward) as a function of time t. Assume the object started by being compressed 19 cm from the equilibrium position (where y=0), and released. Note: the equilibrium position is defined here as that location of the mass at rest when it is freely hung from the spring, not the unstretched position of the spring with no mass O y(t) = (0.19 m) -sin (0.60 s) Oy(t) = (0.19 m) - cos (0.60) O y(t) = (0.19 m) - cos((0.60 s) - t) 2st O y(t) = (0.19 m) cos 0.60 s Submit Request Answer
Y Part B How long will it take to get to the equilibrium position for the first time? Express your answer to two significant figures and include the appropriate units. μA ? 4 t= Value Units Submit Request Answer Part C What will be its maximum speed? Express your answer to two significant figures and include the appropriate units. HA → Umax Value Units Constants
Part D What will be the object's maximum acceleration? Express your answer to two significant figures and include the appropriate units. μA ? amax Value = Units Submit Request Answer ▼ Part E Where will the object's maximum acceleration first be attained? O release point O equilibrium point Submit Request Answer ▼