-30.0 cm Object -30.0 cm 10.0 cm -20.0 cm- = 10.0 cm =20.0 cm (a) -15.0 cm- Lens 1 ܕܐ -20.0 cm- (b) -6.67 cm Lens 2 PRA

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answerhappygod
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-30.0 cm Object -30.0 cm 10.0 cm -20.0 cm- = 10.0 cm =20.0 cm (a) -15.0 cm- Lens 1 ܕܐ -20.0 cm- (b) -6.67 cm Lens 2 PRA

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-30.0 cm Object -30.0 cm 10.0 cm -20.0 cm- = 10.0 cm =20.0 cm (a) -15.0 cm- Lens 1 ܕܐ -20.0 cm- (b) -6.67 cm Lens 2

PRACTICE IT = Use the worked example above to help you solve this problem. Two converging lenses are placed d₂ 20.2 cm apart, as shown in figure a, with an object d₁ = 30.3 cm in front of lens 1 on the left. (a) If lens 1 has a focal length of f₁ = 10.1 cm, locate the image formed by this lens and determine its magnification. 9 = 15.15 cm M = -0.5 (b) If lens 2 on the right has a focal length of f₂ = 20.2 cm, locate the image formed and find the total magnification of the system. q = -6.733 cm -1.33 M X = Your response differs from the correct answer by more than 10%. Double check your calculations. EXERCISE HINTS: GETTING STARTED | I'M STUCK! If the two lenses in the figure are separated by 10.1 cm, locate the final image and find the magnification of the system. [Hint: The object for the second lens is virtual!] (Use the necessary information from the Practice It portion of the problem.) q= cm M =
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