14. A parallel plate capacitor of capacitance C as shown in Figure 7 holds energy W = CV². where V is the initial potent

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14 A Parallel Plate Capacitor Of Capacitance C As Shown In Figure 7 Holds Energy W Cv Where V Is The Initial Potent 1 (53.68 KiB) Viewed 41 times

14. A parallel plate capacitor of capacitance C as shown in Figure 7 holds energy W = CV². where V is the initial potential across its circular plates. The capacitor is in vacuum and it is now slowly and completely discharged through a resistor R. C d R Figure 7 (a) Show that the potential, as the system discharges, can be expressed as: V(t) = Voe=¹/RC [4] (b) Using the expression in (a) and neglecting fringe field effects, calculate the electric field E at the edge of the plates. [2] (c) Neglecting fringe field effects, calculate the magnetic field H at the edge of the plates using the generalised Ampere's law. [4] (d) Show the direction of these fields on a diagram similar to the one in Figure 7. [2] (e) Show on the same diagram the direction of the Poynting vector. [1] (f) Calculate the amplitude of the Poynting vector. [2] (g) By using the obtained expression for the Poynting vector, show that the total energy radiating out of the gap between the plates is equal to W. [5]