- This Section Contains Two Problems Typical Of Problems Encountered In The High School Mathematics Curriculum And A Set 1 (10.48 KiB) Viewed 24 times
- This Section Contains Two Problems Typical Of Problems Encountered In The High School Mathematics Curriculum And A Set 2 (36.35 KiB) Viewed 24 times
- This Section Contains Two Problems Typical Of Problems Encountered In The High School Mathematics Curriculum And A Set 3 (21.39 KiB) Viewed 24 times
For each problem and its corresponding set of student solutions, complete the following: (a) Take 5 minutes to attempt to solve the problem yourself (without appealing to sources such as a (b) Examine each of the student solutions to the problem. In writing, indicate ways in which each student was "on-track." Identify errors, misconceptions, or incorrect assumptions revealed in each textbook, or looking at the student solutions). student's written work. (c) Determine whether each student's answer to the problem is correct. (4) Rate each student solution to the problem as high, medium, or low, (e) Compare and discuss with a classmate or in a small group the rating you gave each student solution and the criteria you used in deciding whether a solution was rated high, medium, or low. (0) Now give each student solution a numerical score. First, determine the total number of points that you would assign to this problem, and then determine the number of points you would give for each student solution (for example, 5 out of 8 points). (g) Compare and discuss your numerical scores with a classmate or in a small group. (b) Construct at least two ideal solutions to problem t employ different solution strategies. PROBLEM 1. Find an equation for the line that is parallel to 2x+3y=7 and contains the point (4, 10). Student Solution 1: 2(4) = 3(10) = d 8 + 30 = 38 5/5 2x - 3y = 38 Student Solution 2: 3y=-2x + 7 Y³ 3×13 y-10 = -7/3/(x-4) - 73 y = 3x + 3/3-²3 +10 y = -x + 15
Student Solution 3: vile Student Solution 4: A(5) 5 Student Solution 5: Student Solution 6: M y= mx +b Ax By C 10-23 (4) +6 10 -12 +6 + ما - : 10 b.16 y=x+16) 3512x-7 9:3x-3 y-10= 3 (x-4) 9-10=²x-8/₂ 3y-30=2x-8 3y-2x = 22 yama+b 3y = -2x+7 Sare slepe 10-3(4)+3 3y=+2x+7 M= ²/ (x-4)=y-10 3x-2-y-10 y= 2x+4