Exercise: Develop an IPR curve for the well described below. The drainage radius is 1490 ft and the skin effect is zero.

[answerhappygod]

Exercise Develop An Ipr Curve For The Well Described Below The Drainage Radius Is 1490 Ft And The Skin Effect Is Zero 1 (365.42 KiB) Viewed 28 times

Exercise: Develop an IPR curve for the well described below. The drainage radius is 1490 ft and the skin effect is zero. 1.6 k = 13 md (from cores) 1.5 köhỹ[1 – 0.2(Pwƒ/p) – 0.8(Pwƒ/P)²] 254.2 Boo[In(0.472re/rw)+s] 90 == h = 115 ft 1.4 Pi = 4350 psi Pb = 4350 psi 1.3 1.2 1.1 When p = 4350 psi, Co 1.2 x 10-5 Cw = 3 x 10-6 1.0 0 4000 5000 3000 Pressure (psi) Psi-1 Psi-1 Cf = 3.1 x 10-6 90 = 1411. 1-0.2 - 0.8 1411 [1 - 0.8 (Por) P p c₁ = 1.25 × 10-5 psi-¹ x F = 1.7 cp Ho 5000 Yo = 32° API Yg = 0.71 4000 T = 180°F 3000 5000 Tpc = 395°R Ppc = 667 psi 2000 3000 Pressure (psi) 2000 Sw = 0.3 1000 0 5000 2000 3000 4000 Pressure (psi) $ = 0.21 rw = 0.406 ft Bo (res BBI/STB) B. (res ft³/SCF) R$ (SCF/STB) 0.020 0.016 0.012 0.008 0.004 0.000 1000.0 800.0 600.0 400.0 200.0 0.0 0 0 1000 1000 1000 2000 4000 Flowing Bottomhole Pressure, p (psi) p=4350 0 500 1500 1000 Flowrate, q (STB/d) The IPR curve is no longer straight line!