OBJECT: THE OBJECT OF THIS EXPERIMENT IS TO STUDY TWO EXAMPLES OF SIMPLE HARMONIC MOTION, THE VIBRATING SPRING AND THE S

Post by **answerhappygod** » Thu May 05, 2022 5:33 pm

: Object The Object Of This Experiment Is To Study Two Examples Of Simple Harmonic Motion The Vibrating Spring And The S 1 (58.75 KiB) Viewed 36 times

: Object The Object Of This Experiment Is To Study Two Examples Of Simple Harmonic Motion The Vibrating Spring And The S 2 (54.22 KiB) Viewed 36 times

: Object The Object Of This Experiment Is To Study Two Examples Of Simple Harmonic Motion The Vibrating Spring And The S 3 (64.35 KiB) Viewed 36 times

: Object The Object Of This Experiment Is To Study Two Examples Of Simple Harmonic Motion The Vibrating Spring And The S 4 (53.97 KiB) Viewed 36 times

: Object The Object Of This Experiment Is To Study Two Examples Of Simple Harmonic Motion The Vibrating Spring And The S 5 (50.42 KiB) Viewed 36 times

: Object The Object Of This Experiment Is To Study Two Examples Of Simple Harmonic Motion The Vibrating Spring And The S 6 (50.53 KiB) Viewed 36 times

: Object The Object Of This Experiment Is To Study Two Examples Of Simple Harmonic Motion The Vibrating Spring And The S 7 (45.14 KiB) Viewed 36 times

OBJECT: THE OBJECT OF THIS EXPERIMENT IS TO STUDY TWO EXAMPLES OF SIMPLE HARMONIC MOTION, THE VIBRATING SPRING AND THE SIMPLE PENDULUM. Study: Chapter 10 in your textbook Physics, Cutnell/Johnson INTRODUCTION: A. The Vibrating Spring In Part A we use the spring as an example of simple harmonic motion. An object undergoes simple harmonic motion when it is subject to a force proportional to its displacement from an equilibrium position. The law governing this motion is known as Hooke's Law and is given by F=-kx (1) Where F is the restoring force and the minus sign indicates that the vibrating force and the displacement, x, are in opposite directions. The proportionality constant, k, is the force constant of the spring. When a mass suspended from the lower end of the spring is displaced a small amount and then released, it will vibrate with simple harmonic motion. The period of vibration T is given by the equation T=2x-√ (2) Equation (2) is true only when the mass of the spring m, is negligible in comparison to m elleeeeeeeeeeee Figure 1. Set up for studying the motion of a mass on the end of a spring.
the vibrating mass m. However, when he mass of the spring cannot be neglected, the equivalent mass of the vibrating system equals that of the suspended mass plus one-third the mass of the spring (See Sears, Zemansky & Young, University Physics, 5th Ed. Addison Wesley, p. 202, 1979). Thus, the mass m in Equation (2) must be replaced by Met mass hung on the end of the spring (m) + 1/3 mass of the spring and equation (2) becomes I=2== (3) APPARATUS: 1. Spiral Spring and rigid support. 2. Set of weights 3. Meterstick 4. Quadruple-beam balance Figure 2. Spiral Spring on a rigid Support PROCEDURE A. FOR VIBRATING SPRING 1. Weigh and record the mass of the spring. 2. Suspend the spring from the rigid support with the smaller diameter attached to the support as shown in Figure 2. 3. Place a meter stick vertically close to the spring with the 100cm end resting on the the table top. Use the bottom end of the spring as a reference point. Record this M
TABLE 1. Data For Spring Constant k Mass of Spring m Load On Spring Meterstick Scale m+m/3 m Elongation For Each Load (cm) Reading (cm) (gm) (gm) 0 50 100 150 200 250 300 TABLE 2. Data For The Period Of The Spring Load On Spring Time for 50 Vibrations (sec) m Period Time For One Vibration (sec) Period From Equation 3 (sec) Percent Difference (gm) 100 150 200 250 300 ANALYSIS FOR SPRING: 1. Plot the stretch of the spring (x) versus mg and determine k from the slope of the curve SHM 3
2. Use Equation (3) to calculate the period of the vibrating motion using k obtained in step 1 and adding 1/3 the mass of the spring to each mass (m) hung on the spring. 3. Compare the value of T obtained from Equation (3) with the observed value of the period from steps 6 and 7 of PROCEDURE A. 4. Calculate the percent difference. QUESTIONS: 1. Why is it not necessary to add 1/3 of the mass of the spring to the load when plotting the graph to obtain k? 2. Calculate the value for T from Equation (3) without adding 1/3 of the mass of the spring and compare it to the value obtained from step 2 of the above analysis. Find the percent error. 3. Use equation (2) to plot T versus m and plot equation (3) T² versus Me How do those 2 graphs differ? 4. (a) At what point in the path did the spring exert the greatest force on the suspended mass? And at what point was the acceleration greatest? (b) At what point in the path was the velocity greatest? 5. Using the value of k that you obtained from your experiment, calculate the potential energy stored in the spring when it is stretched 5cm. 6. Do small changes in the amplitude of the vibration influence the period? Explain! 7. A particle of mass m=0.5kg has a force exerted on it such that F=-0.65x, where x
EXP-6 Simple Harmonic (1) Fa-Rx Kooke's Low (2) T=2=√₁ splng mais 25 O) T=25√√ Metf this Jumm Meff = m+spring hi-nga Elongetin в проїку-х Elongation for load (cm) 0 <-Shyer [] - डॉट Part A: . Mass of spring m, = 162.55g Table 1: Data for Spring constant K Load on spring m(gm) Ruler Reading (cm) 0 24.2 50 29.9 100 35.4 150 41.8 200 48.3 250 53.7 300 59.7 Table 2: Data for Period of the Spring Load on Spring m(gm) 100 150 200 spring Time for 20 vibrations (sec) 17 20 22
Part A: ● Mass of spring m, = 162.55g Table 1: Data for Spring constant K Load on spring m(gm) Ruler Reading (cm) 0 24.2 50 29.9 100 35.4 150 41.8 200 48.3 53.7 -350100 59.7 Table 2: Data for Period of the Spring Load on Spring m(gm) 100 150 200 250 300 Time for 20 vibrations (sec) 17 20 22 24 26 Elongation for load (cm) 0
Simple pendulum. e xam F-- -7-20√15 (5) Slope Part B: . Diameter of sphere - 2.8cm Table 3: Period of pendulum for small displacement 8 - 10" Length of string (cm) Length of Pendulum Number of vibrations (cm) 90 91.4 81.4 71.4 61.4 51.4 41.4 31.4 Table 4: Period of pendulum with displacement 8 40 and 1=30cm Number of vibrations Time for 20 vibrations 20 25.86 8888888 70 60 40 30 T²5²0 RRRRRRR 20 20 20 20 20 20 e < 10⁰ e-extring + reake th 402 g 20 gsid=9.0 / 472 ^g slope Ya vecer Time for 20 vibrations (sec) 38.80 35.90 33.70 31.08 28.36 25.38 21.98