Page 1 of 1

Solve for VDS V₂0- OF Z; 1.5 kQ2 +15 V 3.3 ΚΩ HE IDSS = 8 mA Vp = -2.8 V Zo Solve for VCE, VBC V₁ Z₁ F 390 ΚΩ 12 V B =

Posted: Thu May 05, 2022 2:06 pm
by answerhappygod
 1
1 (38.08 KiB) Viewed 57 times
 2
2 (41.48 KiB) Viewed 57 times
Solve for VDS V₂0- OF Z; 1.5 kQ2 +15 V 3.3 ΚΩ HE IDSS = 8 mA Vp = -2.8 V Zo
Solve for VCE, VBC V₁ Z₁ F 390 ΚΩ 12 V B = 120 ro = 40 ΚΩ Hl ov₂ Z₂ ↑ 5.6 kQ -8 V