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Solve for VCE, VBC V₁ Z₁ F 390 ΚΩ 12 V B = 120 ro = 40 ΚΩ Hl ov₂ Z₂ ↑ 5.6 kQ -8 V
Solve for VDS V₂0- OF Z; 1.5 kQ2 +15 V 3.3 ΚΩ HE IDSS = 8 mA Vp = -2.8 V Zo Solve for VCE, VBC V₁ Z₁ F 390 ΚΩ 12 V B =
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Solve for VDS V₂0- OF Z; 1.5 kQ2 +15 V 3.3 ΚΩ HE IDSS = 8 mA Vp = -2.8 V Zo Solve for VCE, VBC V₁ Z₁ F 390 ΚΩ 12 V B =
Solve for VDS V₂0- OF Z; 1.5 kQ2 +15 V 3.3 ΚΩ HE IDSS = 8 mA Vp = -2.8 V Zo
Solve for VCE, VBC V₁ Z₁ F 390 ΚΩ 12 V B = 120 ro = 40 ΚΩ Hl ov₂ Z₂ ↑ 5.6 kQ -8 V
Solve for VCE, VBC V₁ Z₁ F 390 ΚΩ 12 V B = 120 ro = 40 ΚΩ Hl ov₂ Z₂ ↑ 5.6 kQ -8 V
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