- The Following Table Gives The Joint Probability Function Y1 2 1 3 4 1 0 24 0 12 0 06 0 18 Y2 20 02 0 00 0 08 0 06 3 0 00 1 (119.86 KiB) Viewed 112 times
The following table gives the joint probability function Y1 2 1 3 4 1 0.24 0.12 0.06 0.18 Y2 20.02 0.00 0.08 0.06 3 0.00
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The following table gives the joint probability function Y1 2 1 3 4 1 0.24 0.12 0.06 0.18 Y2 20.02 0.00 0.08 0.06 3 0.00
The following table gives the joint probability function Y1 2 1 3 4 1 0.24 0.12 0.06 0.18 Y2 20.02 0.00 0.08 0.06 3 0.00 0.08 0.16 0.00 Find the conditional distribution of Y2, given Y1=1 O 1 2 3 Y2ly1=1 Ply2ly1= 1) 6/7 1/7 0 O y2ly1=1 1 2 3 Ply2 ly1= 1) 0.9 0.1 0 O 1 3 y2|y1=1 Ply2l y1= 1) 12/13 1/13 0 y2|y1=1 1 2 3 Ply2|y1= 1) 0.75 0.25 0 O y2ly1=1 1 2 3 Plyz|y1=1) 0.24 0.02 0
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