If FCC crystal has 4 atoms basis {(000), (1/2 1/2 0), (0 1/2 1/2 ), (1/2 0 1/2)} and BCC has 2 atoms basis {(000), (1/2

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answerhappygod
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If FCC crystal has 4 atoms basis {(000), (1/2 1/2 0), (0 1/2 1/2 ), (1/2 0 1/2)} and BCC has 2 atoms basis {(000), (1/2

Post by answerhappygod »

If FCC crystal has 4 atoms basis {(000), (1/2 1/2 0), (0 1/2 1/2
), (1/2 0 1/2)}
and BCC has 2 atoms basis {(000), (1/2 1/2 1/2)}
In similar way can you define the atom basis for Tetragonal,
Orthorhombic and Hexagonal?
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