Results T(°C) T(K) (from data table) T 3*10^-3 45 318 K 35 308 K 3 10^-3 25 298 K 3 10^-3 15 288 K 3 10^-3 1 5 5 278 K 4

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Results T C T K From Data Table T 3 10 3 45 318 K 35 308 K 3 10 3 25 298 K 3 10 3 15 288 K 3 10 3 1 5 5 278 K 4 1 (41.5 KiB) Viewed 34 times

Results T(°C) T(K) (from data table) T 3*10^-3 45 318 K 35 308 K 3 10^-3 25 298 K 3 10^-3 15 288 K 3 10^-3 1 5 5 278 K 4 10^-3 1 rate = Thus In(k)= In(rate) Why can rate be used instead of k? Note that rate= k[IO, [[H], so that i -In([10][1][H]), where the second term is constant because the same concentrations were used in all [10]14[0-j[*]** experiments. This term is then combined with In(A), and changes the y-intercept of the graph, but not the slope, which is all that is needed to find the activation energy. Run 1 2 3 4 Avg. Rate (from data table) 0.83 1.0 1 Ln(rate) H