The equilibrium number of voids of aluminum at 500 degrees is 7.55*10^23 m^-3. What is the activation energy at the time
Posted: Wed May 04, 2022 3:27 pm
The equilibrium number of voids of aluminum at 500 degrees is
7.55*10^23 m^-3. What is the activation energy at the time of
activation when a void is formed? (However, the atomic weight and
density of aluminum at 500°C are 26.98 g/mol and 2.62 g/cm^3,
respectively.)
7.55*10^23 m^-3. What is the activation energy at the time of
activation when a void is formed? (However, the atomic weight and
density of aluminum at 500°C are 26.98 g/mol and 2.62 g/cm^3,
respectively.)