The equilibrium number of voids of aluminum at 500 degrees is 7.55*10^23 m^-3. What is the activation energy at the time

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answerhappygod
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The equilibrium number of voids of aluminum at 500 degrees is 7.55*10^23 m^-3. What is the activation energy at the time

Post by answerhappygod »

The equilibrium number of voids of aluminum at 500 degrees is
7.55*10^23 m^-3. What is the activation energy at the time of
activation when a void is formed? (However, the atomic weight and
density of aluminum at 500°C are 26.98 g/mol and 2.62 g/cm^3,
respectively.)
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