X X X X X X X X X X B 100 X XX X +V

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X X X X X X X X X X B 100 X Xx X V 1 (6.59 KiB) Viewed 52 times

A uniform electric field is established between the plates
of a parallel plate capacitor by holding one plate at ground and
the other at a positive potential V as shown. A uniform magnetic
field B is established perpendicular to the electric field (Fig). A
charge −q is released from rest from the lower plate.
i) Write down the equations of motion for the
velocity components of the charge.
ii) Show that, at some time t later, the velocity
of the electron in the xdirection is related to the distance y
moved along the y-axis by vx = ωy
iii) By applying the conservation of energy or
otherwise to determine the square of the velocity in the x–y-plane,
show that
v2y= (2qv/md)y- ω2 y2
X X X X X X X X X X B 100 X XX X +V