001 Part 1 Of 3 10 0 Points An Oscillating Emf Drives A Series Com Bination Of A Resistor And An Air Gap Ca Pacitor W 1 (60.3 KiB) Viewed 36 times
001 Part 1 Of 3 10 0 Points An Oscillating Emf Drives A Series Com Bination Of A Resistor And An Air Gap Ca Pacitor W 2 (37.17 KiB) Viewed 36 times
001 (part 1 of 3) 10.0 points An oscillating emf drives a series com bination of a resistor and an air-gap ca- pacitor with circular plates, with emf on (220 V) sin[(800 radians/s) t], resistance of 0.7 MM, radius of 31 cm, and separation of 1.6 mm, as shown below. 0.7 ΜΩ 31 cm ♡ 1.6 mm circular plate capacitor (220 V) sin[(800 radians/s) t] Find the rms current Irms in the resis- tor. The speed of light is 2.99792 x 10³ m/s, the permeability of free space is 4 x 10-7 T m/A, and the permittivity of free space is 8.85419 x 10-¹2 C²/N-m². Answer in units of mA. 002 (part 2 of 3) 10.0 points Find the rms value of the displacement cur- rent between the capacitor plates. Answer in units of mA. 003 (part 3 of 3) 10.0 points Find the rms value of the induced magnetic field strength between the capacitor plates at a distance of 30 cm from the center of the plates. Answer in units of T.
(a) Capaiternice s 23 C = A = E₁tr² = 8185x²√³² x TLX 0.31² = d d 116x103 1.669x10¹ F = Impdence; Z= R² + (c)² (6+1+xX68³ )² + (1 661xX10³ x 800) @7x108³) rms Value of current: Irons = · Irms = V (b) Troms = 2:07x104 = 0·2017 MA (1) Magnetic field; B = Mor Irms 2TR2 4x107x 0.31 x 0.2077x103 2πx 0.312 B = 1.34 X10¹ T 71489x105R = = 220 √₂x+1489x105 √₂ Z 2.077x104A = 0.2017 MA
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