Complete the sequence of steps to determine if &(1, 2) = 1s(1)a(1)1s(2)ß(2) + 1s(2)a(2)1s(1)ß(1) is an eigenfunction of
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Complete the sequence of steps to determine if &(1, 2) = 1s(1)a(1)1s(2)ß(2) + 1s(2)a(2)1s(1)ß(1) is an eigenfunction of
Complete the sequence of steps to determine if &(1, 2) = 1s(1)a(1)1s(2)ß(2) + 1s(2)a(2)1s(1)ß(1) is an eigenfunction of the operator Ŝz. Match the items in the left column to the appropriate blanks in the expression on the right. Reset Help ħ Ŝz [1s (1) a (1)1s (2) B(2) + 1s(2)a(2)1s(1)ß(1)] ħ (Ŝz1+ Ŝz2) [18(1)a(1)1s(2)ß(2)+ 1s(2)a(2)1s(1)ß(1)] = 2 + 0 1s(2)a(2)1s (1)B(1) Therefore, (1, 2) an eigenfunction of the operator Sz. 1s(1)a(2)1s(2)B(1) 1s(1)a(1)1s(2)B(2) 1s(2)a(1)1s (1)B(2) is not is
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