- Provider 1 23456 7 8 9 10 11 12 13 14 Tv 75 61 63 52 65 72 67 69 68 73 64 76 58 62 Internet 77 62 67 57 67 74 71 73 71 7 1 (7.57 KiB) Viewed 28 times
The accompanying table contains the service ratings of 14 different Internet and TV providers. Complete parts (a) through (d) below. Click the icon to view the data table. C a. At the 0.05 level of significance, is there evidence of a difference in the mean service rating between TV and Internet services? Let μ, be the mean TV service rating and let ₂ be the mean Internet service rating. State the null and alternative hypotheses. Choose the correct answer below. OA. Ho: Ho =0 (where o=₁/₂) © B. Hoi ko =0 (where Ho = H. - Hz) H₁ H₂>0 H₁: Po 20 OC. Ho: Ho=0 (where po ₁-₂) H₁: HD <0 OD. Ho: HD #0 (where po ₁-₂) H₁: H = 0 OE H₂: Ho=0 (where -H₂) H₂H #0 OF. Ho: Mo = 0 (where po ₁/₂) H₁ H₂ #0 The test statistic is tSTAT (Type an integer or a decimal. Round to two decimal places as needed.) The p-value is (Type an integer or a decimal. Round to three decimal places as needed.) Since the p-value is the value of a There is b. What assumption is necessary about the population distribution in order to perform this test? A. It must be assumed that the distribution of the differences between the measurements is approximately uniform. B. It must be assumed that the distribution of the differences between the measurements is approximately normal. C. It must be assumed that the distribution of the differences between the measurements is skewed. D. No assumptions are necessary. evidence of a difference in the mean measurements.