- Hello I Need Help With This Problem 1 (79.35 KiB) Viewed 41 times
Hello I need help with this problem
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answerhappygod
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Hello I need help with this problem
Hello I need help with this problem
HW 7 CLT: Problem 4 (1 point) An HP laser printer is advertised to print text documents at a speed of 18 ppm (pages per minute). The manufacturer tells you that the printing speed is actually a Normal random variable with a mean of 17.54 ppm and a standard deviation of 5 ppm. Suppose that you draw a random sample of 10 printers. Part i) Using the information about the distribution of the printing speeds given by the manufacturer, find the probability that the mean printing speed of the sample is greater than 18.44 ppm. (Please carry answers to at least six decimal places in intermediate steps. Give your final answer to the nearest three decimal places). Probability (as a proportion) Part ii) Use normal approximation to find the probability that more than 48.3% of the sampled printers operate at the advertised speed (i.e. the printing speed is equal to or greater than 18 ppm) O A. 0.4495 OB. 0.4949 OC. 0.5505 O D. 0.5051
HW 7 CLT: Problem 4 (1 point) An HP laser printer is advertised to print text documents at a speed of 18 ppm (pages per minute). The manufacturer tells you that the printing speed is actually a Normal random variable with a mean of 17.54 ppm and a standard deviation of 5 ppm. Suppose that you draw a random sample of 10 printers. Part i) Using the information about the distribution of the printing speeds given by the manufacturer, find the probability that the mean printing speed of the sample is greater than 18.44 ppm. (Please carry answers to at least six decimal places in intermediate steps. Give your final answer to the nearest three decimal places). Probability (as a proportion) Part ii) Use normal approximation to find the probability that more than 48.3% of the sampled printers operate at the advertised speed (i.e. the printing speed is equal to or greater than 18 ppm) O A. 0.4495 OB. 0.4949 OC. 0.5505 O D. 0.5051
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