- The Region In The First Octant Bounded By The Coordinate Planes And The Surface Z 64 X Y Hint First Graph It Usin 1 (95.09 KiB) Viewed 27 times
the region in the first octant bounded by the coordinate planes and the surface z = 64-x² - y. Hint: first graph it usin
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
the region in the first octant bounded by the coordinate planes and the surface z = 64-x² - y. Hint: first graph it usin
the region in the first octant bounded by the coordinate planes and the surface z = 64-x² - y. Hint: first graph it using GeoGebra. Set up using the order dzdydx. Projection onto xy plane, set z=0 in the equation. This will give you y = 64 - x^2. But also remember, you are only considering first octant. After setting up the triple integral, do not calculate by hand - use Wolfraf Alpha the way we did in class. 32,768 3 8192 65,536 9 131,072 15
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!