Solutions for Some Statically Indeterminate Problems (contd.) 1 sin a, LCD = L√2 √√2 LCB=L√5 √√5 L O₂ B L P Bar ADB is s

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Solutions for Some Statically Indeterminate Problems (contd.) 1 sin a, LCD = L√2 √√2 LCB=L√5 √√5 L O₂ B L P Bar ADB is s

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Solutions For Some Statically Indeterminate Problems Contd 1 Sin A Lcd L 2 2 Lcb L 5 5 L O B L P Bar Adb Is S 1
Solutions For Some Statically Indeterminate Problems Contd 1 Sin A Lcd L 2 2 Lcb L 5 5 L O B L P Bar Adb Is S 1 (111.68 KiB) Viewed 36 times
Solutions for Some Statically Indeterminate Problems (contd.) 1 sin a, LCD = L√2 √√2 LCB=L√5 √√5 L O₂ B L P Bar ADB is supported by two wires, CD and CB. A load P is applied at B. The wires have axial rigidity EA. Disregarding the weight of the bar, find the forces in the wires. Ans: Tcs = 1.125 P and sin α₂ = TCD = 1.406 P
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