Problem No 2 A simply supported W350 x 90 girder, 8m long carries a concentrated load P positioned at midpoint point. Th

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Problem No 2 A simply supported W350 x 90 girder, 8m long carries a concentrated load P positioned at midpoint point. Th

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Problem No 2 A Simply Supported W350 X 90 Girder 8m Long Carries A Concentrated Load P Positioned At Midpoint Point Th 1
Problem No 2 A Simply Supported W350 X 90 Girder 8m Long Carries A Concentrated Load P Positioned At Midpoint Point Th 1 (40.5 KiB) Viewed 340 times
Problem No 2 A simply supported W350 x 90 girder, 8m long carries a concentrated load P positioned at midpoint point. The beam also camies a uniform load of KN/m (including its own weight) and live load of 7.2 kN/m. Use ty = 250 MPa and E 200 GPa. Properties of W 350 x 90 d = 350 mm x= 206.4 x 10 64 mm 3 tu - 10 mm Sx 1510 x 10 mm³ bf = 250 mm tf = 16.5 mm Allowable stresses Allowable deflection = 4/60 0.Goty Flexure, Fb 0.66 # Shear, Fv 0.40 Fy Determine the value of P based on flexure. Determine the value of P based on shear. Determine the value of P based on deflection.
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