Part E Two square conducting plates with sides of length L are separated by a distance D. A dielectric slab with constan

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Part E Two Square Conducting Plates With Sides Of Length L Are Separated By A Distance D A Dielectric Slab With Constan 1 (56.7 KiB) Viewed 53 times

Part E Two square conducting plates with sides of length L are separated by a distance D. A dielectric slab with constant K with dimensions L x L x D is inserted a distance into the space between the plates, as shown in (Figure 1). if F is the force exerted on the slab by the charges on the plates, then du should equal the work done against this force to move the slab a distance dr. Thus dU= -Fdr. Applying this expression to the result of part B, does the electric force on the slab push it out of the capacitor or pull it into the capacitor? O A force pushes the slab out of the capacitor O A force pulls the slab into the capacitor. Submit Request Answer Figure < 1 of 1 > Part F Calculate the magnitude of the force. (This method does not require knowledge of the nature of the fringing field.) Express your answer in terms of the variables K, L, D, V, and constant co. GAZO 0 ? Dielectric slab, constant K F = Submit Request Answer KD