A thin film of oil (ny = 1.2) floats on the surface of a material of refractive index n = 1.65. The arrangement is illum

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A thin film of oil (ny = 1.2) floats on the surface of a material of refractive index n = 1.65. The arrangement is illum

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A Thin Film Of Oil Ny 1 2 Floats On The Surface Of A Material Of Refractive Index N 1 65 The Arrangement Is Illum 1
A Thin Film Of Oil Ny 1 2 Floats On The Surface Of A Material Of Refractive Index N 1 65 The Arrangement Is Illum 1 (56.34 KiB) Viewed 66 times
A thin film of oil (ny = 1.2) floats on the surface of a material of refractive index n = 1.65. The arrangement is illuminated by 5.8 x 10-7 m light that falls at an angle of 34 on the surface of the film. A large region of the film appears bright. Incident light ng (film) d n (material) a) (5 points) The sine of the angle of refraction 0, at the air-film interface is given by: sin(34) 1.2 sin(34) sin(34) 1.2 1.65 1.65 b) (5 points) Calculate 0, in degrees. 0, = c) [5 points) Calculate the wavelength is of light in the oil film. i,= d) [5 points) The minimum thickness d of the film is obtained for a value of m such that select one: Om = 0 Om = 2 Om = 3 Om = 1
select one: Om = 0 = Om = 2 Om m = 3 Om m = 1 e) [5 points] Assume 07 28° and ag = 7.5 x 10-7 m. Calculate d. - d =
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