The block with a mass of 130 kg is released with a velocity of 4.8 m/s at s = 1.5 m. If the mass of the spring bumpers A
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The block with a mass of 130 kg is released with a velocity of 4.8 m/s at s = 1.5 m. If the mass of the spring bumpers A
The block with a mass of 130 kg is released with a velocity of 4.8 m/s at s = 1.5 m. If the mass of the spring bumpers A and B can be neglected, what are the maximum deformations of each of the springs due to the collision if you use Conservation of Energy? If the velocity goes to zero when the mass is above the bottom of the chamber, what is this height after the rebound of the mass after the collision? Note: use Newton's Second Law of motion on the mass with a downward air drag force of Fp = (0.1) N and combine the spring forces in the same upward direction. ka = 853 N/m s=1.5 m wwwww kb = . 436 N/m
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