y" + 2y' + 5y = sin x +cos 2x y' + 4y' + 5y = 35e-4x, y(0) = -3, y'(0) = 1

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answerhappygod
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y" + 2y' + 5y = sin x +cos 2x y' + 4y' + 5y = 35e-4x, y(0) = -3, y'(0) = 1

Post by answerhappygod »

Y 2y 5y Sin X Cos 2x Y 4y 5y 35e 4x Y 0 3 Y 0 1 1
Y 2y 5y Sin X Cos 2x Y 4y 5y 35e 4x Y 0 3 Y 0 1 1 (17.36 KiB) Viewed 39 times
Y 2y 5y Sin X Cos 2x Y 4y 5y 35e 4x Y 0 3 Y 0 1 2
Y 2y 5y Sin X Cos 2x Y 4y 5y 35e 4x Y 0 3 Y 0 1 2 (12.89 KiB) Viewed 39 times
Solve with constant coefficients
y" + 2y' + 5y = sin x +cos 2x

y' + 4y' + 5y = 35e-4x, y(0) = -3, y'(0) = 1
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