5. (Unique but improper solution: Heywood case.) Consider an m= 1 factor model for the population with covariance matrix
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5. (Unique but improper solution: Heywood case.) Consider an m= 1 factor model for the population with covariance matrix
5. (Unique but improper solution: Heywood case.) Consider an m= 1 factor model for the population with covariance matrix Σ = 1.4 .4 1 .9 .7 19 .7 1 show that there is a unique choice of L and with E = LL' + , but that < 0, so the choice is not admissible.
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