- As Shown Below In Figure 1 Shaft A In The Gear Mechanism Is Driven By A Planetary Gear Ring Gear W Planet Gear W 1 (68.25 KiB) Viewed 20 times
B. [11 pts total] From the previous question, you know that the planetary gear was operating at a power of 0.8kW and that Gear 1 rotates CCW. From Figure 1, all the gears have a module of m= 4 mm and a pressure angle of a = 20 degrees. The teeth numbers of the gears are summarized in Table 2 below. (Note: If you did not solve for part A, you can assume wa= 500 RPM CCW) Table 2: Summary of the mechanism gear teeth Gear 1 Gear 2 Gear 3 Gear 4 Gear 5 Teeth 14 28 14 35 75 Here, Gears 3 and 4 are rigidly attached to each other, meaning that they rotate together. Also, Gear 2 is an idler, meaning that there is no torque on Shaft B. With these given criterias, identify the following: 1) [3 pts] Based on the power input, what is the resultant torque acting on Gear 1? 2) [5 pts] Draw the free-body diagram for Gear 1. Determine the radial and tangential load Gear 2 applies towards Gear 1 (Also indicate their directions). 3) [3 pts] Draw the free-body diagram for Gear 2. Determine the radial and tangential load Gear 3 applies towards Gear 2 (Also indicate their directions). C. [5 pts] If Gear 5 has an allowable bending stress of 100 MPa, determine what is the appropriate minimum face width of Gear 5. The Lewis form factor for Gear 5 is 0.259, and the speed factor is calculated as shown in the equation below: 6.1+V 6.1 (Note: If you did not solve for part A, you can assume wa= 500 RPM CCW) Κυ