- A Task 4 A Heat Pump Using Refrigerant 134a Heats A House By Using Underground Water At 8 C As The Heat Source The Hous 1 (246.32 KiB) Viewed 30 times
a Task 4 A heat pump using refrigerant-134a heats a house by using underground water at 8°C as the heat source. The house is losing heat at a rate of 60,000 kJ/h. The refrigerant enters the compressor at 280 kPa and 0°C, and it leaves at 1 MPa and 60°C. The refrigerant exits the condenser at 30°C. Determine (1) Using didactic sketches, evaluate the operating principles of a heat pump. (2) The power input to the heat pump (3) the rate of heat absorption from the water (4) Calculate the COP of this heat pump (5) The increase in electric power input if an electric resistance heater is used instead of a heat pump (6) Investigate the effect of varying the compressor isentropic efficiency over the 100 percent). Plot the power input to the compressor and the electric power saved by using a heat pump rather than electric resistance heating as functions of compressor efficiency and discuss the results. (7) In order to increase the COP of the heat pump, what recommendations or improvements would you suggest? explain your recommendations. range [60 to