Question 1 (20 points): Given the following truth SOP: Y(A,B,C,D) = (1,3,5,6,10,11,13) Build the truth table. B Y A 0 O 0 0 0 ololaan C 0 O 1 1 O 0 1 1 obor 1 1 1 1 D O 1 0 1 O 1 0 1 0 1 0 1 ca -obble 1 1 1 1 1 1 1 olo 0 1 0 1 1 1 1 Using the above truth table, implement the circuit using the 74153 (4-to-1 multiplexer) chip and any necessary extra logic gates. Notes: You must use 1 MUX only. You must use the minimum number of extra logic gates. A and B are the selection lines. You must show the steps you did to get the logic expressions. B is the most significant bit 1G is the enable line for the first MUX (active low) - 2G is the enable line for the second MUX (active low)
74153
Question 1 (20 points): Given the following truth SOP: Y(A,B,C,D) = (1,3,5,6,10,11,13) Build the truth table. B Y A 0 O
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Question 1 (20 points): Given the following truth SOP: Y(A,B,C,D) = (1,3,5,6,10,11,13) Build the truth table. B Y A 0 O
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