b) Now exploit the distributive property of multiplication for ordinary numbers, i.e. the fact that for any three number
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b) Now exploit the distributive property of multiplication for ordinary numbers, i.e. the fact that for any three number
b) Now exploit the distributive property of multiplication for ordinary numbers, i.e. the fact that for any three numbers a, b, and c we have that a(b + c) = ab + bc to show that, for any number c and any two vectors i and i we have that c(i + ) = cü + cu
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