4 Question la For the vectors A 8.00 - 3.00f and B -2.00 - 9.00f, determine the angle between them. (b) Assuming the x-axis points to the right, express the vectors in the following figure in vector component form (ie, in terms of the unit vectors and D 20.4 a) A + B = 6.0? +6.05 -> Gitan (60 = 45° p=0 (+3) Ã B = A Blosd - A B x + A, B, A = √8.00 13.00 = 8.544 B=J.. . 9.2195 les (+X b) = 1.360568* _ 0.35in 60. 8 = -20.4 cos 370? + 20.9 sin 37 } .
Question 2 The position of a particle moving along the x-axis is given by x(i) - br - cr', where b - 7.70 m/s and - 3.30 m/s. x is expressed in meters when is entered in seconds. Determine the following. (a) The particle's average velocity between 1 1.0 sandr-3.0 s. (b) The particle's acceleration at any time. (c) The particle's location when it changes direction. 2 X(t) = bt- ct v(t) = b-dict alt) = -2( v(3.00) = (2.7 */) - 2/3,3 %/²) (3.0s) = -12.1% (1.0,) = (1.1%) - 1(3.3^/,») (.0.) = 1 Vorg - = -6.6 m/s) n ) 1(1) =-26 =-(3.5"/3) = 66.6%) (constant) b-dct = 0 => b=hct => x (1.17) = 6.1) (1-12) – (3.3) (1.17) * = (1.49
Question 3 A bullet is shot from Shoulder height(1.50m) at an angle 60.0° above the horizontal with an initial speed of 400 m/s. Neglect air resistance (a) How much time elapses before the bullet hits the ground? (b) How far does the bullet travel horizontally? (e) What is the bullet's impact angle when landing on the ground? Vo = Vx Vy= Vosine V-7: 346.41 Y-% + Vryt - 2gt² => 0= 1,5 +246.11)+ - 4.96 -b! Jina = 10.7 - Hool 34 (+1) (v: Vcos (6-)= doo/ Vygt VSin (6:1)-9.2(10.1) 1) X=0 + ((400) (70.7) 22,280.014 7: (60), somloos) 28.00m H - 2x9.8 Range = (1 in (120) = 14139.190m 9.8 x = 14134.19 7=7069.597 - 38000 A = tan' (-888.5-883,05 of 23.01 below the Horizont
4 Question la For the vectors A 8.00 - 3.00f and B -2.00 - 9.00f, determine the angle between them. (b) Assuming the x-a
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4 Question la For the vectors A 8.00 - 3.00f and B -2.00 - 9.00f, determine the angle between them. (b) Assuming the x-a
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