The position of a squirrel running in a park is given by r⃗ =[(0.280m/s)t+(0.0360m/s2)t2]i^+ (0.0190m/s3)t3j^. Part APar

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The position of a squirrel running in a park is given by r⃗=[(0.280m/s)t+(0.0360m/s2)t2]i^+ (0.0190m/s3)t3j^.
Part APart complete What is υx(t), the x-component of thevelocity of the squirrel, as function of time?vx(t)=(0.280m/s)t+(0.0720m/s2)t2 vx(t)=(0.0720m/s2)tvx(t)=0.280m/s+(0.0720m/s2)t vx(t)=0.280m/s Previous AnswersCorrect
Part BPart complete What is υy(t), the y-component of thevelocity of the squirrel, as function of time? vy(t)=(0.0570m/s3)t2vy(t)=(0.0570m/s2)t2 vy(t)=(0.0570m/s3)tvy(t)=(0.0570m/s3)t+(0.0720m/s2)t2 Previous Answers Correct
Part C At 5.58 s , how far is the squirrel from its initialposition? Express your answer to three significant figures andinclude the appropriate units. r = Previous AnswersRequestAnswer
Part D At 5.58 s , what is the magnitude of the squirrel'svelocity? Express your answer to three significant figures andinclude the appropriate units. v = StartFraction m Over sEndFraction
Part E At 5.58 s , what is the direction (in degreescounterclockwise from +x-axis) of the squirrel's velocity? Expressyour answer to three significant figures and include theappropriate units. θ = nothing nothing