The position of a squirrel running in a park is given byř = [(0.280 m/s)t + (0.0360 m/s?)t?]{+ (0.0190 m/s°)+' ġ.

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The Position Of A Squirrel Running In A Park Is Given Byr 0 280 M S T 0 0360 M S T 0 0190 M S G 1 (16.35 KiB) Viewed 39 times

Part C
At 4.80 ss , how far is the squirrel from its initialposition?
Express your answer to three significant figures and include theappropriate units.
Part D
At 4.80 ss , what is the magnitude of the squirrel'svelocity?
Express your answer to three significant figures and include theappropriate units.
Part E
At 4.80 ss , what is the direction (in degrees counterclockwisefrom +x-axis) of the squirrel's velocity?
Express your answer to three significant figures and include theappropriate units.
The position of a squirrel running in a park is given byř = [(0.280 m/s)t + (0.0360 m/s?)t?]{+ (0.0190 m/s°)+' ġ.