what does net force equals in this graph or question. why does F[net] = f[w] sin angle -F[f]? and why does force of tension equals Mg- Ma in second graph
What Does Net Force Equals In This Graph Or Question Why Does F Net F W Sin Angle F F And Why Does Force O 1 (490.03 KiB) Viewed 37 times
What Does Net Force Equals In This Graph Or Question Why Does F Net F W Sin Angle F F And Why Does Force O 2 (782.26 KiB) Viewed 37 times
is me sind all me sille akes a 30° angle with find the acceleration of Example 18 A block slides down an inclined plane that makes a 30° the horizontal. If the coefficient of kinetic friction is 0.3, hnd the accel below, the weight the block. parallel to s scalar components: f. Sin e parall Solution. First draw a free-body diagram. Notice that, in the diagram shown below of the block, F = mg, has been written in terms of the ramp and F. cos normal to the ramp: EN TLF Fsin e Fw cos o The force of friction, F., that acts up the ramp (opposite to the direction in which the block slides) has magnitude F- uF. But the diagram shows that FN = F.cos , so F = u(mg cosa Therefore, the net force down the ramp is - ucos ) F sin - F = mg sin 0 - umg cos 0 = mg(sin Then, setting Fequal to ma, we solve for a: a Fe - mg(sin 0 - ucos 6) m = g(sin - ucos e) = (10 m/s?) (sin 30° -0.3 cos 30°) = 2.4 m/s?
10 ly 250 N, while 1, and the crate will not slide. he cords that fthe tension force in the corda wever any strings are ne direction of the tension multiply the force by box pulley Note t equati M Newt
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