I don't understand how it is 11 micromol/ minute I only get 1.1I have added my work below.
More Michaelis-Menten. For an enzyme that follows simple MichaelisMenten kinetics, what is the value of VmaxmaxVmax if VV0 is equal to 1 μ mol minute −1 at 10KMM ? (4)
?? V0=1 at W kmm V0=Vnax kn+[8][5] Vmax =1.1 V0=Vm2Km+[k][10 km] V0=Vmata 1110 Vmant V0=1110 V0Vminx=1011⋅V0 Vminx=1011⋅1 Vwat =1.1
More Michaelis-Menten. For an enzyme that follows simple MichaelisMenten kinetics, what is the value of VmaxmaxVmax if
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More Michaelis-Menten. For an enzyme that follows simple MichaelisMenten kinetics, what is the value of VmaxmaxVmax if
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