A mixture of 0.06053 mol of CH4, 0.05044 mol of H2S, 0.07902 molof CS2, and 0.01635 mol of H2 is placed in a 1.0-L steel pressurevessel at 1304 K. The following equilibrium is established:
1 CH4(g) + 2 H2S(g) 1 CS2(g) + 4 H2(g)
At equilibrium 0.01316 mol of H2 is found in the reactionmixture.
(a) Calculate the equilibrium partial pressures of CH4, H2S,CS2, and H2.
Peq(CH4) = ________
Peq(H2S) = ________
Peq(CS2) = ________
Peq(H2) = ________
(b) Calculate KP for this reaction. KP = _________
A mixture of 0.06053 mol of CH4, 0.05044 mol of H2S, 0.07902 mol of CS2, and 0.01635 mol of H2 is placed in a 1.0-L stee
-
answerhappygod
- Site Admin
- Posts: 899604
- Joined: Mon Aug 02, 2021 8:13 am
A mixture of 0.06053 mol of CH4, 0.05044 mol of H2S, 0.07902 mol of CS2, and 0.01635 mol of H2 is placed in a 1.0-L stee
Join a community of subject matter experts. Register for FREE to view solutions, replies, and use search function. Request answer by replying!