How many grams of oxygen gas (31.9988 g/mol) are required to completely combust 49.37g of methanol (32.0419 g/mol)? 2 CH

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answerhappygod
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How many grams of oxygen gas (31.9988 g/mol) are required to completely combust 49.37g of methanol (32.0419 g/mol)? 2 CH

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How many grams of oxygen gas (31.9988 g/mol) are required to completely combust 49.37g of methanol (32.0419 g/mol)?
2 CH3OH(g) + 3 02(8) > 2 CO2(g) + 4 H20(g)
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